Friday, 20 February 2015

Task-6 Calculate the flatband voltage.

The flatband condition is defined as the applied voltage is 0, and in this case, the capacitance equals to the oxide capacitance in series with the Debye capacitance. Which is:
From the reference handout

Where the Debye capacitance
The interpretation of the required variables are listed below:
Permittivity in free space - 8.85e(-12) F/M
Relative permittivity for silicon – 11.7
Charge carried by an electron – 1.602e(-19)
Maximum capacitance (read from the given txt file) - 2.919e3 pF
Acceptor concentration –  4.088e(21) /m^3
Capacitor area – 2.375829444e(-7)
Thermal voltage – 25 mV
Therefore,
The flatband capacitance is

According to the txt file, the flatband voltage should be in the interval between 0.93 and 0.94 V.

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